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When performing a forced checkout, treat files as modified when the workdir or the index is identical except for the mode. This ensures that force checkout will update the mode to the target. (Apply this check for regular files only, if one of the items was a file and the other was another type of item then this would be a typechange and handled independently.)
On Windows, we do not support file mode changes, so do not test for type changes between the disk and tree being checked out. We could have false positives since the on-disk file can only have an (effective) mode of 0100644 since NTFS does not support executable files. If the tree being checked out did have an executable file, we would erroneously decide that the file on disk had been changed.
Test that we can successfully force checkout a target when the file contents are identical, but the mode has changed.
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I cherry-picked these from #3839. I think that there's more work to do there, but this is nice and isolated and we should include it. /cc @cjhoward92 |
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Looks good to me, thanks @ethomson. I've verified locally that the test actually catches the chmodded file with |
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When performing a forced checkout, treat files as modified when the workdir or the index is identical except for the mode. This ensures that force checkout will update the mode to the target.
Without this change, we examine the contents of the file on-disk and determine that it's identical to the tree we're checking out, and continue without making any changes. By including the filemode in the difference check, checkout will now make a file executable (or remove the executable bit) as appropriate to match the checkout target.
We apply this check for regular files only: in the case where one of the items was a file and the other item was not, then this would be a typechange (not a file mode change) and would be handled by other codepaths.